=(4x^2-1)-(x^2+2)

Solution for =(4x^2-1)-(x^2+2) equation:

Simplifying
0 = (4x2 + -1) + -1(x2 + 2)

Reorder the terms:
0 = (-1 + 4x2) + -1(x2 + 2)

Remove parenthesis around (-1 + 4x2)
0 = -1 + 4x2 + -1(x2 + 2)

Reorder the terms:
0 = -1 + 4x2 + -1(2 + x2)
0 = -1 + 4x2 + (2 * -1 + x2 * -1)
0 = -1 + 4x2 + (-2 + -1x2)

Reorder the terms:
0 = -1 + -2 + 4x2 + -1x2

Combine like terms: -1 + -2 = -3
0 = -3 + 4x2 + -1x2

Combine like terms: 4x2 + -1x2 = 3x2
0 = -3 + 3x2

Solving
0 = -3 + 3x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
0 + -3x2 = -3 + 3x2 + -3x2
Remove the zero:
-3x2 = -3 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-3x2 = -3 + 0
-3x2 = -3

Divide each side by '-3'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}